What is the antipode of Pozuelo de Alarcón, Spain?

The antipode of Pozuelo de Alarcón, Spain (40.43293°, -3.81338°) is located near Palmerston North, New Zealand (-40.35636°, 175.61113°). The antipodal distance is approximately 49.59 km.

What is on the opposite side of the world from Pozuelo de Alarcón?

On the exact opposite side of the Earth from Pozuelo de Alarcón, Spain, you would find a point in the ocean or land near Palmerston North, New Zealand. This is calculated by inverting the latitude and adding/subtracting 180° from the longitude.

Antipode of Pozuelo de Alarcón, Spain

About the Antipode of Pozuelo de Alarcón

An antipode is the point on Earth's surface that is diametrically opposite to a given location. For Pozuelo de Alarcón, Spain (population: 82,428), located at coordinates 40.4329°, -3.8134°, the antipodal point falls near Palmerston North, New Zealand (population: 90,500).

How is the Antipode Calculated?

To find the antipode of any location:

Latitude: Invert the sign (40.4329° becomes -40.4329°)
Longitude: Add or subtract 180° (-3.8134° becomes 175.6111°)

The exact antipodal coordinates for Pozuelo de Alarcón are -40.4329°, 176.1866°.

Explore More Antipodes

Curious about other cities? Check out our complete list of 1,000 antipodal city pairs, ranked by proximity. Or use the Antipode Finder to search any location on Earth.