The antipode of Calbayog City, Philippines is located near Sinop, Brazil. The exact antipodal point is at coordinates -11.8642°, -55.5025°, which is approximately 24.86 km from Sinop.
An antipode is the point on Earth's surface that is diametrically opposite to a given location. For Calbayog City, Philippines (population: 67,921), located at coordinates 12.0668°, 124.5962°, the antipodal point falls near Sinop, Brazil (population: 116,013).
To find the antipode of any location:
The exact antipodal coordinates for Calbayog City are -12.0668°, -55.4038°.
Curious about other cities? Check out our complete list of 1,000 antipodal city pairs, ranked by proximity. Or use the Antipode Finder to search any location on Earth.