What is the antipode of Arganzuela, Spain?

The antipode of Arganzuela, Spain (40.40021°, -3.69618°) is located near Palmerston North, New Zealand (-40.35636°, 175.61113°). The antipodal distance is approximately 59.02 km.

What is on the opposite side of the world from Arganzuela?

On the exact opposite side of the Earth from Arganzuela, Spain, you would find a point in the ocean or land near Palmerston North, New Zealand. This is calculated by inverting the latitude and adding/subtracting 180° from the longitude.

Antipode of Arganzuela, Spain – Opposite Side of Earth

About the Antipode of Arganzuela

An antipode is the point on Earth's surface that is diametrically opposite to a given location. For Arganzuela, Spain (population: 148,797), located at coordinates 40.4002°, -3.6962°, the antipodal point falls near Palmerston North, New Zealand (population: 90,500).

How is the Antipode Calculated?

To find the antipode of any location:

Latitude: Invert the sign (40.4002° becomes -40.4002°)
Longitude: Add or subtract 180° (-3.6962° becomes 175.6111°)

The exact antipodal coordinates for Arganzuela are -40.4002°, 176.3038°.

Explore More Antipodes

Curious about other cities? Check out our complete list of 1,000 antipodal city pairs, ranked by proximity. Or use the Antipode Finder to search any location on Earth.